# 100 watt solar panel kit

We sell tons of solar panels for DIY off-grid solar projects. Generally, once we design a solar energy system, we start together with your loads, what you’re trying to power, and from there you work out what size solar array you would like. But now, we are getting to check out it the opposite way around, what are you able to power with a 100W solar array? A solar panel is rated by the quantity of power it creates at Standard Test Conditions, or STC. These conditions include the intensity of the sun, 1000 watt per square metre, the angle of the sunshine hitting the panel directly, the temperature, 25℃ or 77℉, and other criteria. So as they assert, actual mileage may vary, supported all of those factors within the world.

We generally reduce the calculations supported the difference between the lab setting and your actual installation. When a 12V solar array is rated at 100W, that’s an instant rating, if all of the test conditions are met, once you measure the output, the voltage are going to be about 18 volts and therefore the current are going to be 5.55 amps. Since watts equals volts times amps, 18 volts x 5.55 amps = 100 watts. Watts is just like the speed of a car, miles per hour, how briskly is it going at that instant, 50 miles per hour. to work out what proportion power is generated over a period of your time, you’ll to multiply the watts times the amount of hours it’s running. So in one hour, 100W x 1 hour = 100 watt hours. Again, together with your car, 50 miles per hour x one hour equals 50 miles.

Now that we all know the maths behind it, we’d like to work out what percentage hours to plug into the equation to work out what proportion power the solar array will generate during a day. what percentage hours of sunlight that’s adequate to the intensity of ordinary test conditions, which is essentially the sun at noon, will the solar array be exposed to during the day? the amount of hours of sunlight adequate to noon is named insolation, or sun hours. As you well know, albeit the sun is up at 8 within the morning, it’s not as bright because it is at noon. So you can’t just say that the sun is shining for 10 hours, so I’ll multiple 100W x 10 hours. The hour between 8 and 9 within the morning is perhaps only half as strong because the sun from noon to 1 within the afternoon, therefore the morning hour would probably only be adequate to ½ sun hour. But the times are such a lot shorter within the winter than the summer, the amount of sun hours would be dramatically different throughout the year. Also, the quantity of sunlight I’d get in MiamI, FL would vary than the quantity of sun hours I’d get in Portland, ME.

Luckily, some very smart people have taken decades worth of weather data and calculated out the amount of sun hours for everywhere the planet, broken out by month, and even the lean angle that the panels are mounted. So I can check out the charts to ascertain if I even have a 100W solar array, in Portland, ME installed at about 45 degrees angle, on annual average, I’d get 4.6 sun hours each day. Likewise, if I took that very same solar array in Miami FL, installed it at a 25 degree tilt, I’d have an annual average of 5.2 sun hours. even as a touch aside, i would like to form sure you see that in the months of June and July, I’m getting to get more power out of that solar array in Maine than i will be able to in Florida. With Miami being closer to the equator and Maine being closer to the North Pole, the times are longer within the summer in Maine, then the sun shines on the solar panels longer. quite cool, huh?

OK, back to the question at hand, what am i able to power with a 100W solar panel? i want to work out my worst case scenario, what’s the worst performing month that I’ll be using the panel? Since, for this instance, I’m getting to be using it in Maine, during ski season, i want to work on December. So how am i able to squeeze out the maximum amount power as I possibly can in December? By tilting the solar array steeper so it points right at the low winter sun. So I’m getting to mount my 100W solar array at 60 degrees and figure on 3.2 sun hours. I’ll now take 100W x 3.2 sun hours and obtain 320 watt hours each day in December. Now, as you recognize, nothing in real world is ideal, so I even have to work in losses that I’ll likely incur, like drop across the wire, dirt (or snow) accumulating on the solar array, losses through the charge controller, etc. So I’m getting to multiply the 320 watt hours times .7. I know, that’s figuring on losing about ⅓ of your power. I now find yourself with 224 watt hours of power that I even have made with my 100W solar array on a December day.

What am i able to do thereupon power? Well, first of all i want to store it during a battery in order that I can use it later once I need it. So, I’m getting to use a minimum of a 7 amp charge controller to manage putting the facility into a deep cycle battery which will be charged and discharged on a daily basis. What size battery do I need? Sorry, that involves more math. I even have my 224 watt hours that I’m making, and I’m putting it during a 12 volt battery. Because watts divided by volts equals amps, 224 watt hours divided by 12 volts equals 18.6 amp hours. albeit I’m putting it during a deep cycle battery, most batteries still don’t like being drained down quite half way, so I’m getting to confirm i buy A battery which will hold a minimum of twice the maximum amount power i will be able to be using, so I’ll only use half the facility in it. 18.6 amp hours x 2 = 37.2 amp hours. the quantity of power A battery can store changes counting on the temperature of the space it’s in. If my battery goes to be as cold as 60 degrees Fahrenheit, i want to extend the dimensions of my battery by 11% to accommodate the cooler temps. 37.2 amp hours x 1.11 = 41.3 amp hours. I’m also getting to be converting the DC power from my battery to AC using an inverter, and I’m getting to lose about 5% of my power through that conversion, so 41.3 amp hours / .95 = 43.4 amp hours.

Now I don’t know if you’ve ever been in Maine within the winter. But trust me on this one, the sun doesn’t shine a day there in December. Not by an extended shot. So i want to work out what percentage days without sun that i want to store the facility for to urge me through those sunless days. Let’s say i want it to last me the weekend without sun. 43.4 amp hours x 2 days = 86.9 amp hours. Great, I’m getting to get myself a gaggle 27 deep cycle battery, that’s 89Ah 12V.

OK, now, I can finally find out what I can do thereupon power. I can run my laptop that uses 45W for five hours. Because 224 Watt hours / 45W = 4.97 hours. Or I can power 3 of my 10W LED lights for 7 hours, and still have a touch power left over. Or I could make myself a cup of coffee, hear the radio while reading a book with a 10W light on for 3 hours, and use my laptop for two hours. this could offer you enough information in order that you’ll find out the way to fit this into your situation. you’ll change the numbers to suit your area, and your power needs.